1 possible answer(s) on “[parser] Illegal arrow expression containing `in` as `for` lhs

  1. for (x=>(x in y);;);

    This is an infinite loop because it’s valid code, and you didn’t provide a condition in the test 😛

    for (x=>(x in y); false;);
    // or
    for (x=>(x in y);;) break;